关于6xk0的精选

解：∵x²-6x+k=0（对应a=1,b=-6,c=k）∴根据韦达定理可知x1+x2=-b/a=6x1x2=c/a=k又∵x1²-x2²-x1-x2=115∴(x1+x2)(x1-x2)-(x1+x2)=115∵x1+x2=6∴6(x1-x2)=121∴x1-x2=121/6这样就可以列个方程组了x1+x2=6①x1-x2=121/6...